S.ABCD ABCD 3a SA = a, SA ⊥ (ABCD)S.ABCD6a39a33a3a33y = f(x)−1−130xy−123Oz = (1 − 2i)21z15√51251√5log3(x −2) = 2x = 11 x = 8 x = 9 x = 1039π 18π 12π 36πy = −x3+ 3x2−4(2; +∞) (0; 2) (−∞; 0) ∪ (2; +∞) (−∞; 0)I =2Z1x − 1xdxI = 1 + ln 2 I =74I = 2 ln 2 I = 1 − ln 2(N) 3 15π(N)12π 16π 45π 36πP =3vuut233s23r23P =2318P =2312P =2318P =23118 z =(2 − 3i)(4 − i)3 + 2izOxy(1; 4) (1; −4) (−1; −4) (−1; 4)Oxyz (P ) 2x −2y + z + 2017 = 0(P )n = (4; −4; 2) n = (1; −2; 2) n = (1; −1; 4) n = (−2; 2; 1)ABCD.A0B0C0D03ACB0D018√233393183Oxy z|z − 1 + 2i| = |z + 1 + 2i|x + 2y = 0 x − 2y = 0 x − 2y + 1 = 0 x + 2y + 1 = 0R = 3, h = 5.V = 90π V = 45π V = 15π V = 45y =x2+ x − 2x2− 3x + 211 − 2x−∞;1212ln(1 − 2x) + C ln |2x −1| + C12ln |2x −1| + C −12ln |2x −1| + COxyz (P ) : 2x − 2y + z + 4 = 0d M(1; 2; 1) (P )d = 1 d =13d = 3 d = 4S.ABC 1 BC EBE = 2EC V SAEBV =13V =23V =43V =16y = log9x2+ 1y0=2x ln 9x2+ 1y0=2 ln 3x2+ 1y0=x(x2+ 1) ln 3y0=1(x2+ 1) ln 9z1z2z2− 4z + 5 = 0 w =1z1+1z2+ i(z12z2+ z...